What are the solutions to the equation (x)(x-6)=135 ?

The solutions to the equation (x)(x-6)=135 are x=15,x=-9

Find the zeros of (x)(x-6)=135

The zeros of (x)(x-6)=135 are x=15,x=-9

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(x) (x - 6) = 135

x = 15, x = - 9

Solution steps

(x) (x - 6) = 135

Expand

(x) (x - 6) : x^{2} - 6 x

x^{2} - 6 x = 135

Move

135

to the left side

x^{2} - 6 x - 135 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 135 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 135) = 24

x_{1, 2} = \frac{- ( - 6 ) \pm 24}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 24}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 24}{2 \cdot 1}

x = \frac{- ( - 6 ) + 24}{2 \cdot 1} : 15

x = \frac{- ( - 6 ) - 24}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 15, x = - 9

9 y^{2} + 21 y - 18 = 0

16 x^{2} + 32 x

15 + 2 y = y^{2}

x^{2} + 8 x + 9

x^{2} + 8 x + 1

What are the solutions to the equation (x)(x-6)=135 ?
The solutions to the equation (x)(x-6)=135 are x=15,x=-9
Find the zeros of (x)(x-6)=135
The zeros of (x)(x-6)=135 are x=15,x=-9