What are the solutions to the equation 9x^2-12x+3=0 ?

The solutions to the equation 9x^2-12x+3=0 are x=1,x= 1/3

Find the zeros of 9x^2-12x+3=0

The zeros of 9x^2-12x+3=0 are x=1,x= 1/3

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9 x^{2} - 12 x + 3 = 0

x = 1, x = \frac{1}{3}

Decimal Notation

x = 1, x = 0.33333 \dots

Solution steps

9 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 3}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 3 = 6

x_{1, 2} = \frac{- ( - 12 ) \pm 6}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6}{2 \cdot 9}, x_{2} = \frac{- ( - 12 ) - 6}{2 \cdot 9}

x = \frac{- ( - 12 ) + 6}{2 \cdot 9} : 1

x = \frac{- ( - 12 ) - 6}{2 \cdot 9} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{3}

3 y^{2} + 4 y = 15

t^{2} - 3 t - 10 = 0

x^{2} + 8 x + 12 = 0

2 x^{2} + 28 x + 82 = 0

2 X^{2} + 8 = 0

What are the solutions to the equation 9x^2-12x+3=0 ?
The solutions to the equation 9x^2-12x+3=0 are x=1,x= 1/3
Find the zeros of 9x^2-12x+3=0
The zeros of 9x^2-12x+3=0 are x=1,x= 1/3