What are the solutions to the equation n^2-5n+12=8 ?

The solutions to the equation n^2-5n+12=8 are n=4,n=1

Find the zeros of n^2-5n+12=8

The zeros of n^2-5n+12=8 are n=4,n=1

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n^{2} - 5 n + 12 = 8

n = 4, n = 1

Solution steps

n^{2} - 5 n + 12 = 8

Move

8

to the left side

n^{2} - 5 n + 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

n_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, n_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

n = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

n = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

n = 4, n = 1

3 m (2 m + 9) = 0

4 x^{2} + 1 = 5

6 r^{2} + 6 r + 12 = 0

(200 + 4 x) (50 + x) = 10000

3 x^{2} - 54 x + 186 = 0

What are the solutions to the equation n^2-5n+12=8 ?
The solutions to the equation n^2-5n+12=8 are n=4,n=1
Find the zeros of n^2-5n+12=8
The zeros of n^2-5n+12=8 are n=4,n=1