What are the solutions to the equation v^{(2)}-7v+6=0 ?

The solutions to the equation v^{(2)}-7v+6=0 are v=6,v=1

Find the zeros of v^{(2)}-7v+6=0

The zeros of v^{(2)}-7v+6=0 are v=6,v=1

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v^{(2)} - 7 v + 6 = 0

v = 6, v = 1

Solution steps

v^{(2)} - 7 v + 6 = 0

Refine

v^{2} - 7 v + 6 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 6 = 5

v_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 1}, v_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 1}

v = \frac{- ( - 7 ) + 5}{2 \cdot 1} : 6

v = \frac{- ( - 7 ) - 5}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

v = 6, v = 1

x^{2} - 14 x + 10 = 0

3 x^{2} - 196 x + 2376 = 0

(3 x - 2)^{2} = x^{2} + (2 x + 2)^{2}

12 x^{2} - 240 x + 864 = 0

x, Z = x^{2} + y^{2}

What are the solutions to the equation v^{(2)}-7v+6=0 ?
The solutions to the equation v^{(2)}-7v+6=0 are v=6,v=1
Find the zeros of v^{(2)}-7v+6=0
The zeros of v^{(2)}-7v+6=0 are v=6,v=1