What are the solutions to the equation 4x^2-16x+64=0 ?

The solutions to the equation 4x^2-16x+64=0 are x=2+2sqrt(3)i,x=2-2sqrt(3)i

Find the zeros of 4x^2-16x+64=0

The zeros of 4x^2-16x+64=0 are x=2+2sqrt(3)i,x=2-2sqrt(3)i

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4 x^{2} - 16 x + 64 = 0

x = 2 + 23 i, x = 2 - 23 i

Solution steps

4 x^{2} - 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 64}{2 \cdot 4}

Simplify

(- 16)^{2} - 4 \cdot 4 \cdot 64 : 163 i

x_{1, 2} = \frac{- ( - 16 ) \pm 16 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 16 3 i}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 16 3 i}{2 \cdot 4}

x = \frac{- ( - 16 ) + 16 3 i}{2 \cdot 4} : 2 + 23 i

x = \frac{- ( - 16 ) - 16 3 i}{2 \cdot 4} : 2 - 23 i

The solutions to the quadratic equation are:

x = 2 + 23 i, x = 2 - 23 i

x, f = 3 x^{2} y

0 = - 4.9 t^{2} + 29 t

0 = - 4.9 t^{2} + 27 t

- 6 x^{2} = x^{2} - 28

x + 1 = (3 x - 1)^{2}

What are the solutions to the equation 4x^2-16x+64=0 ?
The solutions to the equation 4x^2-16x+64=0 are x=2+2sqrt(3)i,x=2-2sqrt(3)i
Find the zeros of 4x^2-16x+64=0
The zeros of 4x^2-16x+64=0 are x=2+2sqrt(3)i,x=2-2sqrt(3)i