What are the solutions to the equation 2x(3x-7)=2x-5 ?

The solutions to the equation 2x(3x-7)=2x-5 are x=(8+sqrt(34))/6 ,x=(8-sqrt(34))/6

Find the zeros of 2x(3x-7)=2x-5

The zeros of 2x(3x-7)=2x-5 are x=(8+sqrt(34))/6 ,x=(8-sqrt(34))/6

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2 x (3 x - 7) = 2 x - 5

x = \frac{8 + 34}{6}, x = \frac{8 - 34}{6}

Decimal Notation

x = 2.30515 \dots, x = 0.36150 \dots

Solution steps

2 x (3 x - 7) = 2 x - 5

Expand

2 x (3 x - 7) : 6 x^{2} - 14 x

6 x^{2} - 14 x = 2 x - 5

Move

5

to the left side

6 x^{2} - 14 x + 5 = 2 x

Move

2 x

to the left side

6 x^{2} - 16 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 6 \cdot 5}{2 \cdot 6}

(- 16)^{2} - 4 \cdot 6 \cdot 5 = 234

x_{1, 2} = \frac{- ( - 16 ) \pm 2 34}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 2 34}{2 \cdot 6}, x_{2} = \frac{- ( - 16 ) - 2 34}{2 \cdot 6}

x = \frac{- ( - 16 ) + 2 34}{2 \cdot 6} : \frac{8 + 34}{6}

x = \frac{- ( - 16 ) - 2 34}{2 \cdot 6} : \frac{8 - 34}{6}

The solutions to the quadratic equation are:

x = \frac{8 + 34}{6}, x = \frac{8 - 34}{6}

5 x^{2} - 10 x - 44 = - 4

3 z^{2} - 9 = 0

x, x^{2} + k (4 x + 17) = 0

x, x^{2} - 2 x + 3 = 0

(x + 1)^{2} = e^{2}

What are the solutions to the equation 2x(3x-7)=2x-5 ?
The solutions to the equation 2x(3x-7)=2x-5 are x=(8+sqrt(34))/6 ,x=(8-sqrt(34))/6
Find the zeros of 2x(3x-7)=2x-5
The zeros of 2x(3x-7)=2x-5 are x=(8+sqrt(34))/6 ,x=(8-sqrt(34))/6