What are the solutions to the equation -6y^2+5y+2=0 ?

The solutions to the equation -6y^2+5y+2=0 are y=-(-5+sqrt(73))/(12),y=(5+sqrt(73))/(12)

Find the zeros of -6y^2+5y+2=0

The zeros of -6y^2+5y+2=0 are y=-(-5+sqrt(73))/(12),y=(5+sqrt(73))/(12)

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- 6 y^{2} + 5 y + 2 = 0

y = - \frac{- 5 + 73}{12}, y = \frac{5 + 73}{12}

Decimal Notation

y = - 0.29533 \dots, y = 1.12866 \dots

Solution steps

- 6 y^{2} + 5 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 6 ) \cdot 2}{2 ( - 6 )}

5^{2} - 4 (- 6) \cdot 2 = 73

y_{1, 2} = \frac{- 5 \pm 73}{2 ( - 6 )}

Separate the solutions

y_{1} = \frac{- 5 + 73}{2 ( - 6 )}, y_{2} = \frac{- 5 - 73}{2 ( - 6 )}

y = \frac{- 5 + 73}{2 ( - 6 )} : - \frac{- 5 + 73}{12}

y = \frac{- 5 - 73}{2 ( - 6 )} : \frac{5 + 73}{12}

The solutions to the quadratic equation are:

y = - \frac{- 5 + 73}{12}, y = \frac{5 + 73}{12}

9 x^{2} - 3 x + 4 = 0

x^{2} - 1.2 x + 0.2 = 0

x, 5 x^{2} - 7 x = 1

x^{(2)} - x - 2 = 0

12 X - 7 X^{2} + 64 = 0

What are the solutions to the equation -6y^2+5y+2=0 ?
The solutions to the equation -6y^2+5y+2=0 are y=-(-5+sqrt(73))/(12),y=(5+sqrt(73))/(12)
Find the zeros of -6y^2+5y+2=0
The zeros of -6y^2+5y+2=0 are y=-(-5+sqrt(73))/(12),y=(5+sqrt(73))/(12)