What are the solutions to the equation x^2-1.2x+0.2=0 ?

The solutions to the equation x^2-1.2x+0.2=0 are x=1,x= 1/5

Find the zeros of x^2-1.2x+0.2=0

The zeros of x^2-1.2x+0.2=0 are x=1,x= 1/5

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x^{2} - 1.2 x + 0.2 = 0

x = 1, x = \frac{1}{5}

Decimal Notation

x = 1, x = 0.2

Solution steps

x^{2} - 1.2 x + 0.2 = 0

Multiply both sides by

10

10 x^{2} - 12 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 10 \cdot 2}{2 \cdot 10}

(- 12)^{2} - 4 \cdot 10 \cdot 2 = 8

x_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 10}, x_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 10}

x = \frac{- ( - 12 ) + 8}{2 \cdot 10} : 1

x = \frac{- ( - 12 ) - 8}{2 \cdot 10} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{5}

x, 5 x^{2} - 7 x = 1

x^{(2)} - x - 2 = 0

12 X - 7 X^{2} + 64 = 0

0 = 6 x^{2} - 30 x + 24

- 2. 5^{2} + 4. 5^{2} = c^{2}

What are the solutions to the equation x^2-1.2x+0.2=0 ?
The solutions to the equation x^2-1.2x+0.2=0 are x=1,x= 1/5
Find the zeros of x^2-1.2x+0.2=0
The zeros of x^2-1.2x+0.2=0 are x=1,x= 1/5