What are the solutions to the equation 36d^2+96d+15=0 ?

The solutions to the equation 36d^2+96d+15=0 are d=-1/6 ,d=-5/2

Find the zeros of 36d^2+96d+15=0

The zeros of 36d^2+96d+15=0 are d=-1/6 ,d=-5/2

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36 d^{2} + 96 d + 15 = 0

d = - \frac{1}{6}, d = - \frac{5}{2}

Decimal Notation

d = - 0.16666 \dots, d = - 2.5

Solution steps

36 d^{2} + 96 d + 15 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 \cdot 36 \cdot 15}{2 \cdot 36}

9 6^{2} - 4 \cdot 36 \cdot 15 = 84

d_{1, 2} = \frac{- 96 \pm 84}{2 \cdot 36}

Separate the solutions

d_{1} = \frac{- 96 + 84}{2 \cdot 36}, d_{2} = \frac{- 96 - 84}{2 \cdot 36}

d = \frac{- 96 + 84}{2 \cdot 36} : - \frac{1}{6}

d = \frac{- 96 - 84}{2 \cdot 36} : - \frac{5}{2}

The solutions to the quadratic equation are:

d = - \frac{1}{6}, d = - \frac{5}{2}

x^{2} - 22 = 44

49 x^{2} = 70 x - 26

x (5 x - 3) = 26

x^{2} = - 24 x

x^{2} + 6 x - 28 = 0

What are the solutions to the equation 36d^2+96d+15=0 ?
The solutions to the equation 36d^2+96d+15=0 are d=-1/6 ,d=-5/2
Find the zeros of 36d^2+96d+15=0
The zeros of 36d^2+96d+15=0 are d=-1/6 ,d=-5/2