What are the solutions to the equation 4x^2-6x-2=0 ?

The solutions to the equation 4x^2-6x-2=0 are x=(3+sqrt(17))/4 ,x=(3-sqrt(17))/4

Find the zeros of 4x^2-6x-2=0

The zeros of 4x^2-6x-2=0 are x=(3+sqrt(17))/4 ,x=(3-sqrt(17))/4

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4 x^{2} - 6 x - 2 = 0

x = \frac{3 + 17}{4}, x = \frac{3 - 17}{4}

Decimal Notation

x = 1.78077 \dots, x = - 0.28077 \dots

Solution steps

4 x^{2} - 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

(- 6)^{2} - 4 \cdot 4 (- 2) = 217

x_{1, 2} = \frac{- ( - 6 ) \pm 2 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 17}{2 \cdot 4}, x_{2} = \frac{- ( - 6 ) - 2 17}{2 \cdot 4}

x = \frac{- ( - 6 ) + 2 17}{2 \cdot 4} : \frac{3 + 17}{4}

x = \frac{- ( - 6 ) - 2 17}{2 \cdot 4} : \frac{3 - 17}{4}

The solutions to the quadratic equation are:

x = \frac{3 + 17}{4}, x = \frac{3 - 17}{4}

2 x^{2} - 4 x + 4 = 2

x, x^{2} + x + 6 = 0

\frac{2}{3} a^{2} - 51 = - 3

n (n - 1) = 72

a, a m^{2} = a^{2} b

What are the solutions to the equation 4x^2-6x-2=0 ?
The solutions to the equation 4x^2-6x-2=0 are x=(3+sqrt(17))/4 ,x=(3-sqrt(17))/4
Find the zeros of 4x^2-6x-2=0
The zeros of 4x^2-6x-2=0 are x=(3+sqrt(17))/4 ,x=(3-sqrt(17))/4