What are the solutions to the equation solvefor x,x^2+x+6=0 ?

The solutions to the equation solvefor x,x^2+x+6=0 are x=-1/2+i(sqrt(23))/2 ,x=-1/2-i(sqrt(23))/2

Find the zeros of solvefor x,x^2+x+6=0

The zeros of solvefor x,x^2+x+6=0 are x=-1/2+i(sqrt(23))/2 ,x=-1/2-i(sqrt(23))/2

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x, x^{2} + x + 6 = 0

x = - \frac{1}{2} + i \frac{23}{2}, x = - \frac{1}{2} - i \frac{23}{2}

Solution steps

x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 6 : 23 i

x_{1, 2} = \frac{- 1 \pm 23 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 23 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 23 i}{2 \cdot 1}

x = \frac{- 1 + 23 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{23}{2}

x = \frac{- 1 - 23 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{23}{2}, x = - \frac{1}{2} - i \frac{23}{2}

\frac{2}{3} a^{2} - 51 = - 3

n (n - 1) = 72

a, a m^{2} = a^{2} b

1 2^{2} + 3^{2} = x^{2}

2 x^{2} + 3 = 5 x

What are the solutions to the equation solvefor x,x^2+x+6=0 ?
The solutions to the equation solvefor x,x^2+x+6=0 are x=-1/2+i(sqrt(23))/2 ,x=-1/2-i(sqrt(23))/2
Find the zeros of solvefor x,x^2+x+6=0
The zeros of solvefor x,x^2+x+6=0 are x=-1/2+i(sqrt(23))/2 ,x=-1/2-i(sqrt(23))/2