What are the solutions to the equation 3(x-1)^2-4(x-1)-7=0 ?

The solutions to the equation 3(x-1)^2-4(x-1)-7=0 are x= 10/3 ,x=0

Find the zeros of 3(x-1)^2-4(x-1)-7=0

The zeros of 3(x-1)^2-4(x-1)-7=0 are x= 10/3 ,x=0

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3 (x - 1)^{2} - 4 (x - 1) - 7 = 0

x = \frac{10}{3}, x = 0

Decimal Notation

x = 3.33333 \dots, x = 0

Solution steps

3 (x - 1)^{2} - 4 (x - 1) - 7 = 0

Expand

3 (x - 1)^{2} - 4 (x - 1) - 7 : 3 x^{2} - 10 x

3 x^{2} - 10 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 0}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 0 = 10

x_{1, 2} = \frac{- ( - 10 ) \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10}{2 \cdot 3}, x_{2} = \frac{- ( - 10 ) - 10}{2 \cdot 3}

x = \frac{- ( - 10 ) + 10}{2 \cdot 3} : \frac{10}{3}

x = \frac{- ( - 10 ) - 10}{2 \cdot 3} : 0

The solutions to the quadratic equation are:

x = \frac{10}{3}, x = 0

(3 x - 2) (4 x + 8) = 10 (x - 2) (x + 2)

4 h^{2} - 20 h + 25 = 0

x, x^{2} y^{2} + x y = 6

- 3 x^{2} + 6 = 18

x^{2} + 6 0^{2} = 6 1^{2}

What are the solutions to the equation 3(x-1)^2-4(x-1)-7=0 ?
The solutions to the equation 3(x-1)^2-4(x-1)-7=0 are x= 10/3 ,x=0
Find the zeros of 3(x-1)^2-4(x-1)-7=0
The zeros of 3(x-1)^2-4(x-1)-7=0 are x= 10/3 ,x=0