What are the solutions to the equation 4h^2-20h+25=0 ?

The solutions to the equation 4h^2-20h+25=0 are h= 5/2

Find the zeros of 4h^2-20h+25=0

The zeros of 4h^2-20h+25=0 are h= 5/2

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4 h^{2} - 20 h + 25 = 0

h = \frac{5}{2}

Decimal Notation

h = 2.5

Solution steps

4 h^{2} - 20 h + 25 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

h_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

h = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

h = \frac{5}{2}

The solution to the quadratic equation is:

h = \frac{5}{2}

x, x^{2} y^{2} + x y = 6

- 3 x^{2} + 6 = 18

x^{2} + 6 0^{2} = 6 1^{2}

4 x^{2} - 20 x + 25 = 0

(3 s + 9)^{2} = 25

What are the solutions to the equation 4h^2-20h+25=0 ?
The solutions to the equation 4h^2-20h+25=0 are h= 5/2
Find the zeros of 4h^2-20h+25=0
The zeros of 4h^2-20h+25=0 are h= 5/2