What are the solutions to the equation 21x^2+95=0 ?

The solutions to the equation 21x^2+95=0 are x=sqrt(95/21)i,x=-sqrt(95/21)i

Find the zeros of 21x^2+95=0

The zeros of 21x^2+95=0 are x=sqrt(95/21)i,x=-sqrt(95/21)i

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21 x^{2} + 95 = 0

x = \frac{95}{21} i, x = - \frac{95}{21} i

Solution steps

21 x^{2} + 95 = 0

Move

95

to the right side

21 x^{2} = - 95

Divide both sides by

21

x^{2} = - \frac{95}{21}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{95}{21}, x = - - \frac{95}{21}

- \frac{95}{21} = \frac{95}{21} i

- - \frac{95}{21} = - \frac{95}{21} i

x = \frac{95}{21} i, x = - \frac{95}{21} i

(2 x - 6) (x - 4) (4) = 72

x^{2} + 32 x + 256 = 0

0 = - x^{2} + 4 x - 3

(x + 2)^{2} = \frac{3}{2}

(3 x + 1)^{2} = x + 2

What are the solutions to the equation 21x^2+95=0 ?
The solutions to the equation 21x^2+95=0 are x=sqrt(95/21)i,x=-sqrt(95/21)i
Find the zeros of 21x^2+95=0
The zeros of 21x^2+95=0 are x=sqrt(95/21)i,x=-sqrt(95/21)i