What are the solutions to the equation (k^2)/(1.2)-7=23 ?

The solutions to the equation (k^2)/(1.2)-7=23 are k=6,k=-6

Find the zeros of (k^2)/(1.2)-7=23

The zeros of (k^2)/(1.2)-7=23 are k=6,k=-6

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\frac{k ^{2}}{1.2} - 7 = 23

k = 6, k = - 6

Solution steps

\frac{k ^{2}}{1.2} - 7 = 23

Move

7

to the right side

\frac{k ^{2}}{1.2} = 30

Multiply both sides by

1.2

k^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 36, k = - 36

36 = 6

- 36 = - 6

k = 6, k = - 6

8 x - 65 = x^{2}

t^{2} + 26 t

8 x^{2} + 33 x + 4 = 0

8 x^{2} - 7 x + 3 = 0

5 x^{2} + 30 x + 24 = 64

What are the solutions to the equation (k^2)/(1.2)-7=23 ?
The solutions to the equation (k^2)/(1.2)-7=23 are k=6,k=-6
Find the zeros of (k^2)/(1.2)-7=23
The zeros of (k^2)/(1.2)-7=23 are k=6,k=-6