What are the solutions to the equation 15x^2-8x=-1 ?

The solutions to the equation 15x^2-8x=-1 are x= 1/3 ,x= 1/5

Find the zeros of 15x^2-8x=-1

The zeros of 15x^2-8x=-1 are x= 1/3 ,x= 1/5

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15 x^{2} - 8 x = - 1

x = \frac{1}{3}, x = \frac{1}{5}

Decimal Notation

x = 0.33333 \dots, x = 0.2

Solution steps

15 x^{2} - 8 x = - 1

Move

1

to the left side

15 x^{2} - 8 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 15 \cdot 1}{2 \cdot 15}

(- 8)^{2} - 4 \cdot 15 \cdot 1 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 15}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 15}

x = \frac{- ( - 8 ) + 2}{2 \cdot 15} : \frac{1}{3}

x = \frac{- ( - 8 ) - 2}{2 \cdot 15} : \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{1}{3}, x = \frac{1}{5}

a (a - 6) = 0

2 y^{2} + 2 y - 12 = 0

3 x^{2} - x - 4 = 0

y, x = y^{2} - 4 y + 5

x, y = 2 \cdot x - x^{2}

What are the solutions to the equation 15x^2-8x=-1 ?
The solutions to the equation 15x^2-8x=-1 are x= 1/3 ,x= 1/5
Find the zeros of 15x^2-8x=-1
The zeros of 15x^2-8x=-1 are x= 1/3 ,x= 1/5