What are the solutions to the equation factor 3x^2-x-4=0 ?

The solutions to the equation factor 3x^2-x-4=0 are x=-1,x= 4/3

Find the zeros of factor 3x^2-x-4=0

The zeros of factor 3x^2-x-4=0 are x=-1,x= 4/3

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3 x^{2} - x - 4 = 0

x = - 1, x = \frac{4}{3}

Decimal Notation

x = - 1, x = 1.33333 \dots

Solution steps

3 x^{2} - x - 4 = 0

Factor

3 x^{2} - x - 4 : (x + 1) (3 x - 4)

(x + 1) (3 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or 3 x - 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

3 x - 4 = 0 : x = \frac{4}{3}

The solutions to the quadratic equation are:

x = - 1, x = \frac{4}{3}

y, x = y^{2} - 4 y + 5

x, y = 2 \cdot x - x^{2}

x^{2} - 2 x - 2 = 5

- x^{2} + 4 x + 6

x^{2} - 2 x + 193 = 0

What are the solutions to the equation factor 3x^2-x-4=0 ?
The solutions to the equation factor 3x^2-x-4=0 are x=-1,x= 4/3
Find the zeros of factor 3x^2-x-4=0
The zeros of factor 3x^2-x-4=0 are x=-1,x= 4/3