What are the solutions to the equation 25x^2+9x^2=225 ?

The solutions to the equation 25x^2+9x^2=225 are x=(15)/(sqrt(34)),x=-(15)/(sqrt(34))

Find the zeros of 25x^2+9x^2=225

The zeros of 25x^2+9x^2=225 are x=(15)/(sqrt(34)),x=-(15)/(sqrt(34))

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25 x^{2} + 9 x^{2} = 225

x = \frac{15}{34}, x = - \frac{15}{34}

Decimal Notation

x = 2.57247 \dots, x = - 2.57247 \dots

Solution steps

25 x^{2} + 9 x^{2} = 225

Add similar elements:

25 x^{2} + 9 x^{2} = 34 x^{2}

34 x^{2} = 225

Divide both sides by

34

x^{2} = \frac{225}{34}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{225}{34}, x = - \frac{225}{34}

\frac{225}{34} = \frac{15}{34}

- \frac{225}{34} = - \frac{15}{34}

x = \frac{15}{34}, x = - \frac{15}{34}

x^{2} - 6.4 x = - 1.24

x, z = x^{2} + 2 y^{2}

3 r^{2} + 6 r + 1 = 0

y^{2} + 2 y - 80 = 0

3 x^{2} - 4 x + 1 = 2 x^{2} + 3 x - 4

What are the solutions to the equation 25x^2+9x^2=225 ?
The solutions to the equation 25x^2+9x^2=225 are x=(15)/(sqrt(34)),x=-(15)/(sqrt(34))
Find the zeros of 25x^2+9x^2=225
The zeros of 25x^2+9x^2=225 are x=(15)/(sqrt(34)),x=-(15)/(sqrt(34))