What are the solutions to the equation b^2-12=0 ?

The solutions to the equation b^2-12=0 are b=2sqrt(3),b=-2sqrt(3)

Find the zeros of b^2-12=0

The zeros of b^2-12=0 are b=2sqrt(3),b=-2sqrt(3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

b^{2} - 12 = 0

b = 23, b = - 23

Decimal Notation

b = 3.46410 \dots, b = - 3.46410 \dots

Solution steps

b^{2} - 12 = 0

Move

12

to the right side

b^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 12, b = - 12

12 = 23

- 12 = - 23

b = 23, b = - 23

(3 t + 5) (t - 2) = - 6

x^{2} + 3 x + 20 = 0

5 x^{2} + 21 x + 9 = 5, 5 x^{2} + 21 x + 9 = 5

- 6 x^{2} + 24 x - 30 = 0

- 4.9 x^{2} + 26 x = 0

What are the solutions to the equation b^2-12=0 ?
The solutions to the equation b^2-12=0 are b=2sqrt(3),b=-2sqrt(3)
Find the zeros of b^2-12=0
The zeros of b^2-12=0 are b=2sqrt(3),b=-2sqrt(3)