What are the solutions to the equation (x^2+x-2)=0 ?

The solutions to the equation (x^2+x-2)=0 are x=1,x=-2

Find the zeros of (x^2+x-2)=0

The zeros of (x^2+x-2)=0 are x=1,x=-2

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(x^{2} + x - 2) = 0

x = 1, x = - 2

Solution steps

(x^{2} + x - 2) = 0

Factor

x^{2} + x - 2 : (x - 1) (x + 2)

(x - 1) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

p^{2} + 3 = 0

16 x^{2} - 48 x + 36 = 0

3 (x + 6) (x - 2) = 0

300 - 4.9 t^{2} = 0

x, 2 - 2 x - 3 x^{2} = 0

What are the solutions to the equation (x^2+x-2)=0 ?
The solutions to the equation (x^2+x-2)=0 are x=1,x=-2
Find the zeros of (x^2+x-2)=0
The zeros of (x^2+x-2)=0 are x=1,x=-2