What are the solutions to the equation 24x^2+2x+8=0 ?

The solutions to the equation 24x^2+2x+8=0 are x=-1/24+i(sqrt(191))/(24),x=-1/24-i(sqrt(191))/(24)

Find the zeros of 24x^2+2x+8=0

The zeros of 24x^2+2x+8=0 are x=-1/24+i(sqrt(191))/(24),x=-1/24-i(sqrt(191))/(24)

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24 x^{2} + 2 x + 8 = 0

x = - \frac{1}{24} + i \frac{191}{24}, x = - \frac{1}{24} - i \frac{191}{24}

Solution steps

24 x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 24 \cdot 8}{2 \cdot 24}

Simplify

2^{2} - 4 \cdot 24 \cdot 8 : 2191 i

x_{1, 2} = \frac{- 2 \pm 2 191 i}{2 \cdot 24}

Separate the solutions

x_{1} = \frac{- 2 + 2 191 i}{2 \cdot 24}, x_{2} = \frac{- 2 - 2 191 i}{2 \cdot 24}

x = \frac{- 2 + 2 191 i}{2 \cdot 24} : - \frac{1}{24} + i \frac{191}{24}

x = \frac{- 2 - 2 191 i}{2 \cdot 24} : - \frac{1}{24} - i \frac{191}{24}

The solutions to the quadratic equation are:

x = - \frac{1}{24} + i \frac{191}{24}, x = - \frac{1}{24} - i \frac{191}{24}

4 x^{2} + 5 x - 6

w^{2} - 1 = 0

- x^{2} - x + 7 = 0

x, u = x^{2} + y^{2}

3 (x + 2)^{2} - 15 = 0

What are the solutions to the equation 24x^2+2x+8=0 ?
The solutions to the equation 24x^2+2x+8=0 are x=-1/24+i(sqrt(191))/(24),x=-1/24-i(sqrt(191))/(24)
Find the zeros of 24x^2+2x+8=0
The zeros of 24x^2+2x+8=0 are x=-1/24+i(sqrt(191))/(24),x=-1/24-i(sqrt(191))/(24)