What are the solutions to the equation 4=(x-4)^2 ?

The solutions to the equation 4=(x-4)^2 are x=6,x=2

Find the zeros of 4=(x-4)^2

The zeros of 4=(x-4)^2 are x=6,x=2

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4 = (x - 4)^{2}

x = 6, x = 2

Solution steps

4 = (x - 4)^{2}

Switch sides

(x - 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 4 : x = 6

Solve

x - 4 = - 4 : x = 2

The solutions to the quadratic equation are:

x = 6, x = 2

3 x^{2} - 7 x + 2 = 0

x^{2} + 6 x - 48 = 0

3 x^{2} = - x - 3

- 5 x^{2} + 19 x + 176 = - 7 x^{2} - x

x, - x^{2} + \frac{7}{2} x = \frac{1}{2} x^{2} - 4 x + 6

What are the solutions to the equation 4=(x-4)^2 ?
The solutions to the equation 4=(x-4)^2 are x=6,x=2
Find the zeros of 4=(x-4)^2
The zeros of 4=(x-4)^2 are x=6,x=2