What are the solutions to the equation x^2-24x+20=0 ?

The solutions to the equation x^2-24x+20=0 are x=2(6+sqrt(31)),x=2(6-sqrt(31))

Find the zeros of x^2-24x+20=0

The zeros of x^2-24x+20=0 are x=2(6+sqrt(31)),x=2(6-sqrt(31))

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x^{2} - 24 x + 20 = 0

x = 2 (6 + 31), x = 2 (6 - 31)

Decimal Notation

x = 23.13552 \dots, x = 0.86447 \dots

Solution steps

x^{2} - 24 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 24)^{2} - 4 \cdot 1 \cdot 20 = 431

x_{1, 2} = \frac{- ( - 24 ) \pm 4 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 4 31}{2 \cdot 1}, x_{2} = \frac{- ( - 24 ) - 4 31}{2 \cdot 1}

x = \frac{- ( - 24 ) + 4 31}{2 \cdot 1} : 2 (6 + 31)

x = \frac{- ( - 24 ) - 4 31}{2 \cdot 1} : 2 (6 - 31)

The solutions to the quadratic equation are:

x = 2 (6 + 31), x = 2 (6 - 31)

x^{2} + (- 2) x + 1 = 0

- 0.001 x^{2} + 250 = 0.0006 x^{2} + 0.02 x + 100

B = x^{2} + 3 x + 1

x, z = x^{2} + y

l, T = 2 π l^{2}

What are the solutions to the equation x^2-24x+20=0 ?
The solutions to the equation x^2-24x+20=0 are x=2(6+sqrt(31)),x=2(6-sqrt(31))
Find the zeros of x^2-24x+20=0
The zeros of x^2-24x+20=0 are x=2(6+sqrt(31)),x=2(6-sqrt(31))