What are the solutions to the equation 9x^2+9x+1=0 ?

The solutions to the equation 9x^2+9x+1=0 are x=(-3+sqrt(5))/6 ,x=-(3+sqrt(5))/6

Find the zeros of 9x^2+9x+1=0

The zeros of 9x^2+9x+1=0 are x=(-3+sqrt(5))/6 ,x=-(3+sqrt(5))/6

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9 x^{2} + 9 x + 1 = 0

x = \frac{- 3 + 5}{6}, x = - \frac{3 + 5}{6}

Decimal Notation

x = - 0.12732 \dots, x = - 0.87267 \dots

Solution steps

9 x^{2} + 9 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

9^{2} - 4 \cdot 9 \cdot 1 = 35

x_{1, 2} = \frac{- 9 \pm 3 5}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 9 + 3 5}{2 \cdot 9}, x_{2} = \frac{- 9 - 3 5}{2 \cdot 9}

x = \frac{- 9 + 3 5}{2 \cdot 9} : \frac{- 3 + 5}{6}

x = \frac{- 9 - 3 5}{2 \cdot 9} : - \frac{3 + 5}{6}

The solutions to the quadratic equation are:

x = \frac{- 3 + 5}{6}, x = - \frac{3 + 5}{6}

x^{1 + l o g_{x} (16)} = 4 x^{2}

71 x^{2} - 810 x + 1944 = 0

0.03 q^{2} - 1.2 q + 17 = 0

2 = (x + 2)^{2}

- 5 x^{2} - 3 x - 1 = 0

What are the solutions to the equation 9x^2+9x+1=0 ?
The solutions to the equation 9x^2+9x+1=0 are x=(-3+sqrt(5))/6 ,x=-(3+sqrt(5))/6
Find the zeros of 9x^2+9x+1=0
The zeros of 9x^2+9x+1=0 are x=(-3+sqrt(5))/6 ,x=-(3+sqrt(5))/6