What are the solutions to the equation 0=-x^2+6x-4 ?

The solutions to the equation 0=-x^2+6x-4 are x=3-sqrt(5),x=3+sqrt(5)

Find the zeros of 0=-x^2+6x-4

The zeros of 0=-x^2+6x-4 are x=3-sqrt(5),x=3+sqrt(5)

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0 = - x^{2} + 6 x - 4

x = 3 - 5, x = 3 + 5

Decimal Notation

x = 0.76393 \dots, x = 5.23606 \dots

Solution steps

0 = - x^{2} + 6 x - 4

Switch sides

- x^{2} + 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 4) = 25

x_{1, 2} = \frac{- 6 \pm 2 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 5}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 5}{2 ( - 1 )}

x = \frac{- 6 + 2 5}{2 ( - 1 )} : 3 - 5

x = \frac{- 6 - 2 5}{2 ( - 1 )} : 3 + 5

The solutions to the quadratic equation are:

x = 3 - 5, x = 3 + 5

0 = - x^{2} + 6 x - 7

40 - x^{2} = 0

x^{2} - 33 = 0

\frac{x ^{2}}{4} = x - 2

2 x^{2} + 6 x - 10 = 0

What are the solutions to the equation 0=-x^2+6x-4 ?
The solutions to the equation 0=-x^2+6x-4 are x=3-sqrt(5),x=3+sqrt(5)
Find the zeros of 0=-x^2+6x-4
The zeros of 0=-x^2+6x-4 are x=3-sqrt(5),x=3+sqrt(5)