What are the solutions to the equation 2x^2+6x=-2 ?

The solutions to the equation 2x^2+6x=-2 are x=(-3+sqrt(5))/2 ,x=-(3+sqrt(5))/2

Find the zeros of 2x^2+6x=-2

The zeros of 2x^2+6x=-2 are x=(-3+sqrt(5))/2 ,x=-(3+sqrt(5))/2

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2 x^{2} + 6 x = - 2

x = \frac{- 3 + 5}{2}, x = - \frac{3 + 5}{2}

Decimal Notation

x = - 0.38196 \dots, x = - 2.61803 \dots

Solution steps

2 x^{2} + 6 x = - 2

Move

2

to the left side

2 x^{2} + 6 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

6^{2} - 4 \cdot 2 \cdot 2 = 25

x_{1, 2} = \frac{- 6 \pm 2 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 6 + 2 5}{2 \cdot 2}, x_{2} = \frac{- 6 - 2 5}{2 \cdot 2}

x = \frac{- 6 + 2 5}{2 \cdot 2} : \frac{- 3 + 5}{2}

x = \frac{- 6 - 2 5}{2 \cdot 2} : - \frac{3 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 5}{2}, x = - \frac{3 + 5}{2}

4 x^{2} - 6 x - 70 = 0

0 = \frac{3 x ^{2}}{5} - \frac{1}{4}

x^{2} - 38 = 0

10 x^{2} - 3 = 0

2 m^{2} - 7 m + 5 = 0

What are the solutions to the equation 2x^2+6x=-2 ?
The solutions to the equation 2x^2+6x=-2 are x=(-3+sqrt(5))/2 ,x=-(3+sqrt(5))/2
Find the zeros of 2x^2+6x=-2
The zeros of 2x^2+6x=-2 are x=(-3+sqrt(5))/2 ,x=-(3+sqrt(5))/2