What are the solutions to the equation -8y+3y^2+4=0 ?

The solutions to the equation -8y+3y^2+4=0 are y=2,y= 2/3

Find the zeros of -8y+3y^2+4=0

The zeros of -8y+3y^2+4=0 are y=2,y= 2/3

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- 8 y + 3 y^{2} + 4 = 0

y = 2, y = \frac{2}{3}

Decimal Notation

y = 2, y = 0.66666 \dots

Solution steps

- 8 y + 3 y^{2} + 4 = 0

Write in the standard form

a x^{2} + b x + c = 0

3 y^{2} - 8 y + 4 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 \cdot 4 = 4

y_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 4}{2 \cdot 3}, y_{2} = \frac{- ( - 8 ) - 4}{2 \cdot 3}

y = \frac{- ( - 8 ) + 4}{2 \cdot 3} : 2

y = \frac{- ( - 8 ) - 4}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

y = 2, y = \frac{2}{3}

(3 - x) (- 2 - x) + 6 = 0

7 x^{2} + 4 x + 2 = 0

6 r^{2} - 4 r - 80 = 0

12 x^{2} - 128 x + 252 = 0

y, 5 x^{2} + 2 x^{2} y + y^{2} = 8

What are the solutions to the equation -8y+3y^2+4=0 ?
The solutions to the equation -8y+3y^2+4=0 are y=2,y= 2/3
Find the zeros of -8y+3y^2+4=0
The zeros of -8y+3y^2+4=0 are y=2,y= 2/3