What are the solutions to the equation 2800-16x-24x^2=0 ?

The solutions to the equation 2800-16x-24x^2=0 are x=-(1+sqrt(1051))/3 ,x=(sqrt(1051)-1)/3

Find the zeros of 2800-16x-24x^2=0

The zeros of 2800-16x-24x^2=0 are x=-(1+sqrt(1051))/3 ,x=(sqrt(1051)-1)/3

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2800 - 16 x - 24 x^{2} = 0

x = - \frac{1 + 1051}{3}, x = \frac{1051 - 1}{3}

Decimal Notation

x = - 11.13971 \dots, x = 10.47304 \dots

Solution steps

2800 - 16 x - 24 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 24 x^{2} - 16 x + 2800 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 24 ) \cdot 2800}{2 ( - 24 )}

(- 16)^{2} - 4 (- 24) \cdot 2800 = 161051

x_{1, 2} = \frac{- ( - 16 ) \pm 16 1051}{2 ( - 24 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 16 1051}{2 ( - 24 )}, x_{2} = \frac{- ( - 16 ) - 16 1051}{2 ( - 24 )}

x = \frac{- ( - 16 ) + 16 1051}{2 ( - 24 )} : - \frac{1 + 1051}{3}

x = \frac{- ( - 16 ) - 16 1051}{2 ( - 24 )} : \frac{1051 - 1}{3}

The solutions to the quadratic equation are:

x = - \frac{1 + 1051}{3}, x = \frac{1051 - 1}{3}

b^{2} - 3 b - 10 = 0

x^{2} - 2 x + 0.99 = 0

(3 x - 9) (x - 1) = 0

x^{2} + 10 x + 25 = 225

5 x^{2} + 38 - 3 = 0

What are the solutions to the equation 2800-16x-24x^2=0 ?
The solutions to the equation 2800-16x-24x^2=0 are x=-(1+sqrt(1051))/3 ,x=(sqrt(1051)-1)/3
Find the zeros of 2800-16x-24x^2=0
The zeros of 2800-16x-24x^2=0 are x=-(1+sqrt(1051))/3 ,x=(sqrt(1051)-1)/3