What are the solutions to the equation 21c^2-16c-6=1-2c ?

The solutions to the equation 21c^2-16c-6=1-2c are c=1,c=-1/3

Find the zeros of 21c^2-16c-6=1-2c

The zeros of 21c^2-16c-6=1-2c are c=1,c=-1/3

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21 c^{2} - 16 c - 6 = 1 - 2 c

c = 1, c = - \frac{1}{3}

Decimal Notation

c = 1, c = - 0.33333 \dots

Solution steps

21 c^{2} - 16 c - 6 = 1 - 2 c

Move

2 c

to the left side

21 c^{2} - 14 c - 6 = 1

Move

1

to the left side

21 c^{2} - 14 c - 7 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 21 ( - 7 )}{2 \cdot 21}

(- 14)^{2} - 4 \cdot 21 (- 7) = 28

c_{1, 2} = \frac{- ( - 14 ) \pm 28}{2 \cdot 21}

Separate the solutions

c_{1} = \frac{- ( - 14 ) + 28}{2 \cdot 21}, c_{2} = \frac{- ( - 14 ) - 28}{2 \cdot 21}

c = \frac{- ( - 14 ) + 28}{2 \cdot 21} : 1

c = \frac{- ( - 14 ) - 28}{2 \cdot 21} : - \frac{1}{3}

The solutions to the quadratic equation are:

c = 1, c = - \frac{1}{3}

d^{2} + 6 d - 27 = 0

5 x^{2} + 8 x = 10

(y + 2)^{2} = 25

(y + 2)^{2} = 36

x^{2} + 9 x - 12 = 0

What are the solutions to the equation 21c^2-16c-6=1-2c ?
The solutions to the equation 21c^2-16c-6=1-2c are c=1,c=-1/3
Find the zeros of 21c^2-16c-6=1-2c
The zeros of 21c^2-16c-6=1-2c are c=1,c=-1/3