What are the solutions to the equation (y+2)^2=36 ?

The solutions to the equation (y+2)^2=36 are y=4,y=-8

Find the zeros of (y+2)^2=36

The zeros of (y+2)^2=36 are y=4,y=-8

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(y + 2)^{2} = 36

y = 4, y = - 8

Solution steps

(y + 2)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y + 2 = 36 : y = 4

Solve

y + 2 = - 36 : y = - 8

The solutions to the quadratic equation are:

y = 4, y = - 8

x^{2} + 9 x - 12 = 0

0 = x^{2} + 7 x + 12

8 c^{2} - 3 = 93

95 x^{2} + 56 x + 6719 = 0

q^{2} + 40 q = 0

What are the solutions to the equation (y+2)^2=36 ?
The solutions to the equation (y+2)^2=36 are y=4,y=-8
Find the zeros of (y+2)^2=36
The zeros of (y+2)^2=36 are y=4,y=-8