What are the solutions to the equation q^2+40q=0 ?

The solutions to the equation q^2+40q=0 are q=0,q=-40

Find the zeros of q^2+40q=0

The zeros of q^2+40q=0 are q=0,q=-40

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q^{2} + 40 q = 0

q = 0, q = - 40

Solution steps

q^{2} + 40 q = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4 0^{2} - 4 \cdot 1 \cdot 0 = 40

q_{1, 2} = \frac{- 40 \pm 40}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 40 + 40}{2 \cdot 1}, q_{2} = \frac{- 40 - 40}{2 \cdot 1}

q = \frac{- 40 + 40}{2 \cdot 1} : 0

q = \frac{- 40 - 40}{2 \cdot 1} : - 40

The solutions to the quadratic equation are:

q = 0, q = - 40

x = 5 x (1 - x)

3 z^{2} - 4 z + 5 = 0

(x + 4) (x + 3) = 0

- x^{2} + x + \frac{11}{6} = 0

a, \int (x) d x = a^{2}

What are the solutions to the equation q^2+40q=0 ?
The solutions to the equation q^2+40q=0 are q=0,q=-40
Find the zeros of q^2+40q=0
The zeros of q^2+40q=0 are q=0,q=-40