What are the solutions to the equation (3x-2)(7x-4)=0 ?

The solutions to the equation (3x-2)(7x-4)=0 are x= 2/3 ,x= 4/7

Find the zeros of (3x-2)(7x-4)=0

The zeros of (3x-2)(7x-4)=0 are x= 2/3 ,x= 4/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(3 x - 2) (7 x - 4) = 0

x = \frac{2}{3}, x = \frac{4}{7}

Decimal Notation

x = 0.66666 \dots, x = 0.57142 \dots

Solution steps

(3 x - 2) (7 x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or 7 x - 4 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

7 x - 4 = 0 : x = \frac{4}{7}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = \frac{4}{7}

4 x^{2} - 12 x = - 11

y^{2} = 33

y^{2} = 32

3 x^{2} + 4 x - 18 = 0

x^{2} + 18 x + 68 = 0

What are the solutions to the equation (3x-2)(7x-4)=0 ?
The solutions to the equation (3x-2)(7x-4)=0 are x= 2/3 ,x= 4/7
Find the zeros of (3x-2)(7x-4)=0
The zeros of (3x-2)(7x-4)=0 are x= 2/3 ,x= 4/7