What are the solutions to the equation -x^2-x-3=0 ?

The solutions to the equation -x^2-x-3=0 are x=-1/2-i(sqrt(11))/2 ,x=-1/2+i(sqrt(11))/2

Find the zeros of -x^2-x-3=0

The zeros of -x^2-x-3=0 are x=-1/2-i(sqrt(11))/2 ,x=-1/2+i(sqrt(11))/2

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- x^{2} - x - 3 = 0

x = - \frac{1}{2} - i \frac{11}{2}, x = - \frac{1}{2} + i \frac{11}{2}

Solution steps

- x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

Simplify

(- 1)^{2} - 4 (- 1) (- 3) : 11 i

x_{1, 2} = \frac{- ( - 1 ) \pm 11 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 11 i}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 11 i}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 11 i}{2 ( - 1 )} : - \frac{1}{2} - i \frac{11}{2}

x = \frac{- ( - 1 ) - 11 i}{2 ( - 1 )} : - \frac{1}{2} + i \frac{11}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} - i \frac{11}{2}, x = - \frac{1}{2} + i \frac{11}{2}

p^{2} - 5 = 4

x^{2} + 10 x + 12 = 0

12 (- 2 k - 4)^{2} - 1 (- 2 k - 4) - 6 = 0

y, x^{2} - x y + y^{2} = 3

5 x^{2} + 41 x - 36 = 0

What are the solutions to the equation -x^2-x-3=0 ?
The solutions to the equation -x^2-x-3=0 are x=-1/2-i(sqrt(11))/2 ,x=-1/2+i(sqrt(11))/2
Find the zeros of -x^2-x-3=0
The zeros of -x^2-x-3=0 are x=-1/2-i(sqrt(11))/2 ,x=-1/2+i(sqrt(11))/2