What are the solutions to the equation x^2+2^2=5^2 ?

The solutions to the equation x^2+2^2=5^2 are x=sqrt(21),x=-sqrt(21)

Find the zeros of x^2+2^2=5^2

The zeros of x^2+2^2=5^2 are x=sqrt(21),x=-sqrt(21)

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x^{2} + 2^{2} = 5^{2}

x = 21, x = - 21

Decimal Notation

x = 4.58257 \dots, x = - 4.58257 \dots

Solution steps

x^{2} + 2^{2} = 5^{2}

Move

2^{2}

to the right side

x^{2} = 21

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 21, x = - 21

x^{2} - \frac{23}{12} x + \frac{10}{12} = 0

x^{2} + 14 x = - 2

7 x^{2} + 8 x - 22 = 0

x^{2} + 10 x + 16 = 0

(a x + b) (c x - d) = 4 x^{2} - 25

What are the solutions to the equation x^2+2^2=5^2 ?
The solutions to the equation x^2+2^2=5^2 are x=sqrt(21),x=-sqrt(21)
Find the zeros of x^2+2^2=5^2
The zeros of x^2+2^2=5^2 are x=sqrt(21),x=-sqrt(21)