What are the solutions to the equation 3p^2-14p=5 ?

The solutions to the equation 3p^2-14p=5 are p=5,p=-1/3

Find the zeros of 3p^2-14p=5

The zeros of 3p^2-14p=5 are p=5,p=-1/3

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3 p^{2} - 14 p = 5

p = 5, p = - \frac{1}{3}

Decimal

p = 5, p = - 0.33333 \dots

Solution steps

3 p^{2} - 14 p = 5

Move

5

to the left side

3 p^{2} - 14 p - 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 14)^{2} - 4 \cdot 3 (- 5) = 16

p_{1, 2} = \frac{- ( - 14 ) \pm 16}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- ( - 14 ) + 16}{2 \cdot 3}, p_{2} = \frac{- ( - 14 ) - 16}{2 \cdot 3}

p = \frac{- ( - 14 ) + 16}{2 \cdot 3} : 5

p = \frac{- ( - 14 ) - 16}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

p = 5, p = - \frac{1}{3}

3 x^{2} + 11 x = 0

- \frac{1}{2} x^{2} + x + 4 = 0

2 x^{2} - x = 0

x^{2} = 16 x - 63

p, 0 = p + c p (1 - p) - e p (1 - p)

What are the solutions to the equation 3p^2-14p=5 ?
The solutions to the equation 3p^2-14p=5 are p=5,p=-1/3
Find the zeros of 3p^2-14p=5
The zeros of 3p^2-14p=5 are p=5,p=-1/3