What are the solutions to the equation 4x^2-3=-11x ?

The solutions to the equation 4x^2-3=-11x are x= 1/4 ,x=-3

Find the zeros of 4x^2-3=-11x

The zeros of 4x^2-3=-11x are x= 1/4 ,x=-3

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4 x^{2} - 3 = - 11 x

x = \frac{1}{4}, x = - 3

Decimal Notation

x = 0.25, x = - 3

Solution steps

4 x^{2} - 3 = - 11 x

Move

11 x

to the left side

4 x^{2} - 3 + 11 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 11 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

1 1^{2} - 4 \cdot 4 (- 3) = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 4}, x_{2} = \frac{- 11 - 13}{2 \cdot 4}

x = \frac{- 11 + 13}{2 \cdot 4} : \frac{1}{4}

x = \frac{- 11 - 13}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 3

2 x - 1 = - x^{2}

x^{2} - 16 x + 63 = 0

(x + 1) (x - 5) = 7

x^{2} = \frac{7}{10}

y, f = x^{4} y - 3 x^{3} y^{2}

What are the solutions to the equation 4x^2-3=-11x ?
The solutions to the equation 4x^2-3=-11x are x= 1/4 ,x=-3
Find the zeros of 4x^2-3=-11x
The zeros of 4x^2-3=-11x are x= 1/4 ,x=-3