What are the solutions to the equation 1.2h^2-0.6h-10.2=0 ?

The solutions to the equation 1.2h^2-0.6h-10.2=0 are h=(1+sqrt(137))/4 ,h=(1-sqrt(137))/4

Find the zeros of 1.2h^2-0.6h-10.2=0

The zeros of 1.2h^2-0.6h-10.2=0 are h=(1+sqrt(137))/4 ,h=(1-sqrt(137))/4

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1.2 h^{2} - 0.6 h - 10.2 = 0

h = \frac{1 + 137}{4}, h = \frac{1 - 137}{4}

Decimal Notation

h = 3.17617 \dots, h = - 2.67617 \dots

Solution steps

1.2 h^{2} - 0.6 h - 10.2 = 0

Multiply both sides by

10

12 h^{2} - 6 h - 102 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 12 ( - 102 )}{2 \cdot 12}

(- 6)^{2} - 4 \cdot 12 (- 102) = 6137

h_{1, 2} = \frac{- ( - 6 ) \pm 6 137}{2 \cdot 12}

Separate the solutions

h_{1} = \frac{- ( - 6 ) + 6 137}{2 \cdot 12}, h_{2} = \frac{- ( - 6 ) - 6 137}{2 \cdot 12}

h = \frac{- ( - 6 ) + 6 137}{2 \cdot 12} : \frac{1 + 137}{4}

h = \frac{- ( - 6 ) - 6 137}{2 \cdot 12} : \frac{1 - 137}{4}

The solutions to the quadratic equation are:

h = \frac{1 + 137}{4}, h = \frac{1 - 137}{4}

3 = 3 x^{2} + 8 x

1 x^{2} + 1 x - 2 = 0

1 - 0.5 x + 0.5 x^{2} = 0

0 = (x - 3)^{2} - 1

2 (x - 2)^{2} + 3 = 0

What are the solutions to the equation 1.2h^2-0.6h-10.2=0 ?
The solutions to the equation 1.2h^2-0.6h-10.2=0 are h=(1+sqrt(137))/4 ,h=(1-sqrt(137))/4
Find the zeros of 1.2h^2-0.6h-10.2=0
The zeros of 1.2h^2-0.6h-10.2=0 are h=(1+sqrt(137))/4 ,h=(1-sqrt(137))/4