What are the solutions to the equation m^2-2m-16=0 ?

The solutions to the equation m^2-2m-16=0 are m=1+sqrt(17),m=1-sqrt(17)

Find the zeros of m^2-2m-16=0

The zeros of m^2-2m-16=0 are m=1+sqrt(17),m=1-sqrt(17)

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m^{2} - 2 m - 16 = 0

m = 1 + 17, m = 1 - 17

Decimal Notation

m = 5.12310 \dots, m = - 3.12310 \dots

Solution steps

m^{2} - 2 m - 16 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 16) = 217

m_{1, 2} = \frac{- ( - 2 ) \pm 2 17}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 2 17}{2 \cdot 1}, m_{2} = \frac{- ( - 2 ) - 2 17}{2 \cdot 1}

m = \frac{- ( - 2 ) + 2 17}{2 \cdot 1} : 1 + 17

m = \frac{- ( - 2 ) - 2 17}{2 \cdot 1} : 1 - 17

The solutions to the quadratic equation are:

m = 1 + 17, m = 1 - 17

x^{2} - 4 x - 7 = 0

x^{2} + 10 x + 23 = 0

x, z = 2 x + 4 y - x^{2} - y^{2} - 3

x^{2} + 4 x = 95

x^{2} + 6 x - 71 = 0

What are the solutions to the equation m^2-2m-16=0 ?
The solutions to the equation m^2-2m-16=0 are m=1+sqrt(17),m=1-sqrt(17)
Find the zeros of m^2-2m-16=0
The zeros of m^2-2m-16=0 are m=1+sqrt(17),m=1-sqrt(17)