What are the solutions to the equation 2x^2-1x-1=0 ?

The solutions to the equation 2x^2-1x-1=0 are x=1,x=-1/2

Find the zeros of 2x^2-1x-1=0

The zeros of 2x^2-1x-1=0 are x=1,x=-1/2

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2 x^{2} - 1 x - 1 = 0

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

2 x^{2} - 1 \cdot x - 1 = 0

Refine

2 x^{2} - x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 1) = 3

x_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 2}

x = \frac{- ( - 1 ) + 3}{2 \cdot 2} : 1

x = \frac{- ( - 1 ) - 3}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{2}

(x + 4) (2 x - 1) = 0

x^{2} + 10 x - 96 = 0

4 x^{2} - 10 x - 5 = 0

\frac{2}{7} x^{2} + \frac{7}{2} x = 0

t, x = t^{2}

What are the solutions to the equation 2x^2-1x-1=0 ?
The solutions to the equation 2x^2-1x-1=0 are x=1,x=-1/2
Find the zeros of 2x^2-1x-1=0
The zeros of 2x^2-1x-1=0 are x=1,x=-1/2