What are the solutions to the equation 170=t^2+13t+130 ?

The solutions to the equation 170=t^2+13t+130 are t=(-13+sqrt(329))/2 ,t=(-13-sqrt(329))/2

Find the zeros of 170=t^2+13t+130

The zeros of 170=t^2+13t+130 are t=(-13+sqrt(329))/2 ,t=(-13-sqrt(329))/2

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170 = t^{2} + 13 t + 130

t = \frac{- 13 + 329}{2}, t = \frac{- 13 - 329}{2}

Decimal Notation

t = 2.56917 \dots, t = - 15.56917 \dots

Solution steps

170 = t^{2} + 13 t + 130

Switch sides

t^{2} + 13 t + 130 = 170

Move

170

to the left side

t^{2} + 13 t - 40 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot (- 40) = 329

t_{1, 2} = \frac{- 13 \pm 329}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 13 + 329}{2 \cdot 1}, t_{2} = \frac{- 13 - 329}{2 \cdot 1}

t = \frac{- 13 + 329}{2 \cdot 1} : \frac{- 13 + 329}{2}

t = \frac{- 13 - 329}{2 \cdot 1} : \frac{- 13 - 329}{2}

The solutions to the quadratic equation are:

t = \frac{- 13 + 329}{2}, t = \frac{- 13 - 329}{2}

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0 = - (x - 1)^{2} + 4

2 x^{2} + b x - 3 = 0

4 x^{2} + 14 x - 8 = 0

What are the solutions to the equation 170=t^2+13t+130 ?
The solutions to the equation 170=t^2+13t+130 are t=(-13+sqrt(329))/2 ,t=(-13-sqrt(329))/2
Find the zeros of 170=t^2+13t+130
The zeros of 170=t^2+13t+130 are t=(-13+sqrt(329))/2 ,t=(-13-sqrt(329))/2