What are the solutions to the equation 4q^2+9q+4=0 ?

The solutions to the equation 4q^2+9q+4=0 are q=(-9+sqrt(17))/8 ,q=(-9-sqrt(17))/8

Find the zeros of 4q^2+9q+4=0

The zeros of 4q^2+9q+4=0 are q=(-9+sqrt(17))/8 ,q=(-9-sqrt(17))/8

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4 q^{2} + 9 q + 4 = 0

q = \frac{- 9 + 17}{8}, q = \frac{- 9 - 17}{8}

Decimal Notation

q = - 0.60961 \dots, q = - 1.64038 \dots

Solution steps

4 q^{2} + 9 q + 4 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

9^{2} - 4 \cdot 4 \cdot 4 = 17

q_{1, 2} = \frac{- 9 \pm 17}{2 \cdot 4}

Separate the solutions

q_{1} = \frac{- 9 + 17}{2 \cdot 4}, q_{2} = \frac{- 9 - 17}{2 \cdot 4}

q = \frac{- 9 + 17}{2 \cdot 4} : \frac{- 9 + 17}{8}

q = \frac{- 9 - 17}{2 \cdot 4} : \frac{- 9 - 17}{8}

The solutions to the quadratic equation are:

q = \frac{- 9 + 17}{8}, q = \frac{- 9 - 17}{8}

s^{2} + 2 s + 13 = 0

x, x^{2} + 8 x - 20 = 0

x^{2} + 6 x - 40 = 0

y, \frac{x ^{2}}{81} + \frac{y ^{2}}{144} = 1

45 x^{2} - 3 x = 2 x

What are the solutions to the equation 4q^2+9q+4=0 ?
The solutions to the equation 4q^2+9q+4=0 are q=(-9+sqrt(17))/8 ,q=(-9-sqrt(17))/8
Find the zeros of 4q^2+9q+4=0
The zeros of 4q^2+9q+4=0 are q=(-9+sqrt(17))/8 ,q=(-9-sqrt(17))/8