What are the solutions to the equation s^2+2s+13=0 ?

The solutions to the equation s^2+2s+13=0 are s=-1+2sqrt(3)i,s=-1-2sqrt(3)i

Find the zeros of s^2+2s+13=0

The zeros of s^2+2s+13=0 are s=-1+2sqrt(3)i,s=-1-2sqrt(3)i

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s^{2} + 2 s + 13 = 0

s = - 1 + 23 i, s = - 1 - 23 i

Solution steps

s^{2} + 2 s + 13 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 13 : 43 i

s_{1, 2} = \frac{- 2 \pm 4 3 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 4 3 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 4 3 i}{2 \cdot 1}

s = \frac{- 2 + 4 3 i}{2 \cdot 1} : - 1 + 23 i

s = \frac{- 2 - 4 3 i}{2 \cdot 1} : - 1 - 23 i

The solutions to the quadratic equation are:

s = - 1 + 23 i, s = - 1 - 23 i

x, x^{2} + 8 x - 20 = 0

x^{2} + 6 x - 40 = 0

y, \frac{x ^{2}}{81} + \frac{y ^{2}}{144} = 1

45 x^{2} - 3 x = 2 x

x^{2} + 1 2^{2} = 2 0^{2}

What are the solutions to the equation s^2+2s+13=0 ?
The solutions to the equation s^2+2s+13=0 are s=-1+2sqrt(3)i,s=-1-2sqrt(3)i
Find the zeros of s^2+2s+13=0
The zeros of s^2+2s+13=0 are s=-1+2sqrt(3)i,s=-1-2sqrt(3)i