What are the solutions to the equation factor 4x^2+15x+9=0 ?

The solutions to the equation factor 4x^2+15x+9=0 are x=-3/4 ,x=-3

Find the zeros of factor 4x^2+15x+9=0

The zeros of factor 4x^2+15x+9=0 are x=-3/4 ,x=-3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 15 x + 9 = 0

x = - \frac{3}{4}, x = - 3

Decimal Notation

x = - 0.75, x = - 3

Solution steps

4 x^{2} + 15 x + 9 = 0

Factor

4 x^{2} + 15 x + 9 : (4 x + 3) (x + 3)

(4 x + 3) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 3 = 0 or x + 3 = 0

Solve

4 x + 3 = 0 : x = - \frac{3}{4}

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - 3

0 = 4800 - \frac{3}{4} x^{2}

5 x^{2} - 12 x = - 3

(2 x - 1) (x + 4) = 8 x + 2

8^{2} + 2^{2} = c^{2}

x^{2} - 6 x + c = 0

What are the solutions to the equation factor 4x^2+15x+9=0 ?
The solutions to the equation factor 4x^2+15x+9=0 are x=-3/4 ,x=-3
Find the zeros of factor 4x^2+15x+9=0
The zeros of factor 4x^2+15x+9=0 are x=-3/4 ,x=-3