What are the solutions to the equation (2x-1)(x+4)=8x+2 ?

The solutions to the equation (2x-1)(x+4)=8x+2 are x=2,x=-3/2

Find the zeros of (2x-1)(x+4)=8x+2

The zeros of (2x-1)(x+4)=8x+2 are x=2,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2 x - 1) (x + 4) = 8 x + 2

x = 2, x = - \frac{3}{2}

Decimal Notation

x = 2, x = - 1.5

Solution steps

(2 x - 1) (x + 4) = 8 x + 2

Expand

(2 x - 1) (x + 4) : 2 x^{2} + 7 x - 4

2 x^{2} + 7 x - 4 = 8 x + 2

Move

2

to the left side

2 x^{2} + 7 x - 6 = 8 x

Move

8 x

to the left side

2 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 6) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 2}

x = \frac{- ( - 1 ) + 7}{2 \cdot 2} : 2

x = \frac{- ( - 1 ) - 7}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{3}{2}

8^{2} + 2^{2} = c^{2}

x^{2} - 6 x + c = 0

12 x - 200 = \frac{x ^{2}}{225}

4 z^{2} - z - 3 = 0

x^{2} - 3.5 x + 2.5 = 0

What are the solutions to the equation (2x-1)(x+4)=8x+2 ?
The solutions to the equation (2x-1)(x+4)=8x+2 are x=2,x=-3/2
Find the zeros of (2x-1)(x+4)=8x+2
The zeros of (2x-1)(x+4)=8x+2 are x=2,x=-3/2