What are the solutions to the equation k^2=484 ?

The solutions to the equation k^2=484 are k=22,k=-22

Find the zeros of k^2=484

The zeros of k^2=484 are k=22,k=-22

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k^{2} = 484

k = 22, k = - 22

Solution steps

k^{2} = 484

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 484, k = - 484

484 = 22

- 484 = - 22

k = 22, k = - 22

x^{2} - 6 = - x

- x^{2} - 4 x - 4 = - 2

3 x^{2} + 24 x + 50

x, f = x^{2} - 4 y

3 x^{2} + 15 x + 12 = 0

What are the solutions to the equation k^2=484 ?
The solutions to the equation k^2=484 are k=22,k=-22
Find the zeros of k^2=484
The zeros of k^2=484 are k=22,k=-22