What are the solutions to the equation 0=x^2+2x+8 ?

The solutions to the equation 0=x^2+2x+8 are x=-1+sqrt(7)i,x=-1-sqrt(7)i

Find the zeros of 0=x^2+2x+8

The zeros of 0=x^2+2x+8 are x=-1+sqrt(7)i,x=-1-sqrt(7)i

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0 = x^{2} + 2 x + 8

x = - 1 + 7 i, x = - 1 - 7 i

Solution steps

0 = x^{2} + 2 x + 8

Switch sides

x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 8 : 27 i

x_{1, 2} = \frac{- 2 \pm 2 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 7 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 7 i}{2 \cdot 1}

x = \frac{- 2 + 2 7 i}{2 \cdot 1} : - 1 + 7 i

x = \frac{- 2 - 2 7 i}{2 \cdot 1} : - 1 - 7 i

The solutions to the quadratic equation are:

x = - 1 + 7 i, x = - 1 - 7 i

0 = x^{2} + 2 x - 7

5 x^{2} - 10 x + 2 = 0

y = 2.49 \cdot 1 0^{- 3} (1 - \frac{0.5714 - 500 y}{- 2})^{2}

n^{2} + n - 2 = 0

x^{2} = 4 - x^{2}

What are the solutions to the equation 0=x^2+2x+8 ?
The solutions to the equation 0=x^2+2x+8 are x=-1+sqrt(7)i,x=-1-sqrt(7)i
Find the zeros of 0=x^2+2x+8
The zeros of 0=x^2+2x+8 are x=-1+sqrt(7)i,x=-1-sqrt(7)i