What are the solutions to the equation solvefor x,2x^2+x-9=0 ?

The solutions to the equation solvefor x,2x^2+x-9=0 are x=(-1+sqrt(73))/4 ,x=(-1-sqrt(73))/4

Find the zeros of solvefor x,2x^2+x-9=0

The zeros of solvefor x,2x^2+x-9=0 are x=(-1+sqrt(73))/4 ,x=(-1-sqrt(73))/4

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x, 2 x^{2} + x - 9 = 0

x = \frac{- 1 + 73}{4}, x = \frac{- 1 - 73}{4}

Decimal Notation

x = 1.88600 \dots, x = - 2.38600 \dots

Solution steps

2 x^{2} + x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 9) = 73

x_{1, 2} = \frac{- 1 \pm 73}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 73}{2 \cdot 2}, x_{2} = \frac{- 1 - 73}{2 \cdot 2}

x = \frac{- 1 + 73}{2 \cdot 2} : \frac{- 1 + 73}{4}

x = \frac{- 1 - 73}{2 \cdot 2} : \frac{- 1 - 73}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 73}{4}, x = \frac{- 1 - 73}{4}

x^{2} - 28 = 3 x

9 x^{2} + 3 x + 3 = 0

x (x + 2) = - 10

z^{2} = 12

z^{2} = 36

What are the solutions to the equation solvefor x,2x^2+x-9=0 ?
The solutions to the equation solvefor x,2x^2+x-9=0 are x=(-1+sqrt(73))/4 ,x=(-1-sqrt(73))/4
Find the zeros of solvefor x,2x^2+x-9=0
The zeros of solvefor x,2x^2+x-9=0 are x=(-1+sqrt(73))/4 ,x=(-1-sqrt(73))/4