What are the solutions to the equation 9m^2-40m^2+16=0 ?

The solutions to the equation 9m^2-40m^2+16=0 are m= 4/(sqrt(31)),m=-4/(sqrt(31))

Find the zeros of 9m^2-40m^2+16=0

The zeros of 9m^2-40m^2+16=0 are m= 4/(sqrt(31)),m=-4/(sqrt(31))

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9 m^{2} - 40 m^{2} + 16 = 0

m = \frac{4}{31}, m = - \frac{4}{31}

Decimal Notation

m = 0.71842 \dots, m = - 0.71842 \dots

Solution steps

9 m^{2} - 40 m^{2} + 16 = 0

Move

16

to the right side

9 m^{2} - 40 m^{2} = - 16

Add similar elements:

9 m^{2} - 40 m^{2} = - 31 m^{2}

- 31 m^{2} = - 16

Divide both sides by

- 31

m^{2} = \frac{16}{31}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = \frac{16}{31}, m = - \frac{16}{31}

\frac{16}{31} = \frac{4}{31}

- \frac{16}{31} = - \frac{4}{31}

m = \frac{4}{31}, m = - \frac{4}{31}

\frac{64}{36}

k^{2} = 1

\frac{7 π}{2} + \frac{π}{2}

ln (x + 1) - ln (x - 1)

7 (2 x + 4) = 4 (7 - 2 x)

What are the solutions to the equation 9m^2-40m^2+16=0 ?
The solutions to the equation 9m^2-40m^2+16=0 are m= 4/(sqrt(31)),m=-4/(sqrt(31))
Find the zeros of 9m^2-40m^2+16=0
The zeros of 9m^2-40m^2+16=0 are m= 4/(sqrt(31)),m=-4/(sqrt(31))