What are the solutions to the equation (3y-2)^2=-27 ?

The solutions to the equation (3y-2)^2=-27 are y= 2/3+sqrt(3)i,y= 2/3-sqrt(3)i

Find the zeros of (3y-2)^2=-27

The zeros of (3y-2)^2=-27 are y= 2/3+sqrt(3)i,y= 2/3-sqrt(3)i

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(3 y - 2)^{2} = - 27

y = \frac{2}{3} + 3 i, y = \frac{2}{3} - 3 i

Solution steps

(3 y - 2)^{2} = - 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 y - 2 = - 27 : y = \frac{2}{3} + 3 i

Solve

3 y - 2 = - - 27 : y = \frac{2}{3} - 3 i

The solutions to the quadratic equation are:

y = \frac{2}{3} + 3 i, y = \frac{2}{3} - 3 i

x^{2} + 16 x + 19 = 4

x (x + 13) = 30

9 x^{2} = 24 x - 17

x^{2} + 6 x = - 8

x, F = x^{2} - y^{2} z + z^{2}

What are the solutions to the equation (3y-2)^2=-27 ?
The solutions to the equation (3y-2)^2=-27 are y= 2/3+sqrt(3)i,y= 2/3-sqrt(3)i
Find the zeros of (3y-2)^2=-27
The zeros of (3y-2)^2=-27 are y= 2/3+sqrt(3)i,y= 2/3-sqrt(3)i