What are the solutions to the equation 4x^2+54x=280 ?

The solutions to the equation 4x^2+54x=280 are x=4,x=-35/2

Find the zeros of 4x^2+54x=280

The zeros of 4x^2+54x=280 are x=4,x=-35/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 54 x = 280

x = 4, x = - \frac{35}{2}

Decimal Notation

x = 4, x = - 17.5

Solution steps

4 x^{2} + 54 x = 280

Move

280

to the left side

4 x^{2} + 54 x - 280 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 54 \pm 5 4 ^{2} - 4 \cdot 4 ( - 280 )}{2 \cdot 4}

5 4^{2} - 4 \cdot 4 (- 280) = 86

x_{1, 2} = \frac{- 54 \pm 86}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 54 + 86}{2 \cdot 4}, x_{2} = \frac{- 54 - 86}{2 \cdot 4}

x = \frac{- 54 + 86}{2 \cdot 4} : 4

x = \frac{- 54 - 86}{2 \cdot 4} : - \frac{35}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{35}{2}

x^{2} - 15 = 4 x

x^{2} - 6 x + 9 = - 16

2 n^{2} - 8 n - 64 = 0

5 x^{2} - 7 x - 90 = 0

- 6 x^{2} + 7 x = 3 x - 8

What are the solutions to the equation 4x^2+54x=280 ?
The solutions to the equation 4x^2+54x=280 are x=4,x=-35/2
Find the zeros of 4x^2+54x=280
The zeros of 4x^2+54x=280 are x=4,x=-35/2